gdelgado
09-12-2007, 08:35 PM
total network addresses by class:
class A = 2 raised to 7 = 128
128 minus 2 = 126 total network addresses for class A
class B = 2 raised to 14 = 16,384
class C = 2 raised to 21 = 2,097,152
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On pages 97-98 of you ccna study guide 6th ed. for exam 640-802 you explain that class B Addresses have 16,384 unique class B network addresses. This result is not subtracted by 2 as in your explanation of Class A's total network addresses (128-2=126). Same with class C. Does it matter if I say class B has 16,384 network addresses or class B has 16,384 - 2 network addresses?
Thanks for your help
class A = 2 raised to 7 = 128
128 minus 2 = 126 total network addresses for class A
class B = 2 raised to 14 = 16,384
class C = 2 raised to 21 = 2,097,152
************************************************** ***
On pages 97-98 of you ccna study guide 6th ed. for exam 640-802 you explain that class B Addresses have 16,384 unique class B network addresses. This result is not subtracted by 2 as in your explanation of Class A's total network addresses (128-2=126). Same with class C. Does it matter if I say class B has 16,384 network addresses or class B has 16,384 - 2 network addresses?
Thanks for your help