Subnetting doubt..

[sai]

After dividing the network 172.25.0.0 into eight equal subnets,which three IP addresses could be destined for hosts in the third subnet if the command ip subnet-zero is used on the router? (choose three)

A. 172.25.78.243
B. 172.25.98.18
C. 172.25.72.0
D. 172.25.94.255

2^n-2=8
so n=5... so block size will be 16...

where am i wrong? pls help me out..

[Fuzz]

When dealing with subnets using ip subnet-zero, the formula is 2^n=8, so n=3 in this case. As your original network was 172.25.0.0 /16, you will now get 8 subnets with a /19 mask, and a block size of 32.

Now you should be able to work out your subnet addresses, subnet broadcast addresses and valid host addresses in each subnet.