BigCCNA
05-05-2008, 10:44 PM
Can you confirm if this is through anybody?
35. You are designing a network addressing scheme for a small company. You have decided to use the class B network address 172.16.0.0 with subnet mask 255.255.224.0. Considering that the ip subnet-zero command is NOT enabled on the routers, how many subnets and how many hosts per subnet will this allow for?6 subnets with each 8190 hosts
8 subnets with each 8192 hosts
6 subnets with each 8192 hosts
8 subnets with each 8190 hosts
<table border="0" cellpadding="5" cellspacing="0" width="90%"><tbody><tr><td valign="top" width="25%"> Answer(s):</td> <td valign="top">6 subnets with each 8190 hosts
</td></tr><tr><td valign="top" width="30%"> Your Answer(s): </td> <td valign="top">8 subnets with each 8190 hosts
</td></tr></tbody></table>
Explanation:
224 in decimal is 11100000 in binary is (2*2*2) is 8, but since ip subnet-zero is not used, we cannot use Subnet Zero and All-Ones Subnet, hence we have to subtract 2 is 8-2 = 6 subnet. The remaining 13 bits in the host portion (5 in third octet + 8 in last octet) allow for 2^13 - 2 = 8190 hosts per subnet. The 2 must be subtracted from the number of hosts because one is used for the network address and one for the broadcast address of each individual subnet.
35. You are designing a network addressing scheme for a small company. You have decided to use the class B network address 172.16.0.0 with subnet mask 255.255.224.0. Considering that the ip subnet-zero command is NOT enabled on the routers, how many subnets and how many hosts per subnet will this allow for?6 subnets with each 8190 hosts
8 subnets with each 8192 hosts
6 subnets with each 8192 hosts
8 subnets with each 8190 hosts
<table border="0" cellpadding="5" cellspacing="0" width="90%"><tbody><tr><td valign="top" width="25%"> Answer(s):</td> <td valign="top">6 subnets with each 8190 hosts
</td></tr><tr><td valign="top" width="30%"> Your Answer(s): </td> <td valign="top">8 subnets with each 8190 hosts
</td></tr></tbody></table>
Explanation:
224 in decimal is 11100000 in binary is (2*2*2) is 8, but since ip subnet-zero is not used, we cannot use Subnet Zero and All-Ones Subnet, hence we have to subtract 2 is 8-2 = 6 subnet. The remaining 13 bits in the host portion (5 in third octet + 8 in last octet) allow for 2^13 - 2 = 8190 hosts per subnet. The 2 must be subtracted from the number of hosts because one is used for the network address and one for the broadcast address of each individual subnet.