View Full Version : erorr overlaps with FastEthernet0/0
baher 1
08-26-2011, 01:00 PM
i have ip add 10.0.1.0 and i make vlsm
to have 2 network each 30 and 60 hosts
10.0.1.0 /27 ---- 30 shost
10.0.1.32/26 ---- 60 shost
and i make this config.
R0#config t
Enter configuration commands, one per line. End with CNTL/Z.
R0(config)#int f0/0
R0(config-if)#ip add 10.0.1.1 255.255.255.224
R0(config-if)#int f1/0
R0(config-if)#ip add 10.0.1.33 255.255.255.192
% 10.0.1.0 overlaps with FastEthernet0/0
what's wrong
crissa
08-26-2011, 01:15 PM
i have ip add 10.0.1.0 and i make vlsm
to have 2 network each 30 and 60 hosts
10.0.1.0 /27 ---- 30 shost
10.0.1.32/26 ---- 60 shost
and i make this config.
R0#config t
Enter configuration commands, one per line. End with CNTL/Z.
R0(config)#int f0/0
R0(config-if)#ip add 10.0.1.1 255.255.255.224
R0(config-if)#int f1/0
R0(config-if)#ip add 10.0.1.33 255.255.255.192
% 10.0.1.0 overlaps with FastEthernet0/0
what's wrong
Hello,
a /27 with the subnet nask 255.255.255.224 has 32 IP addresses, it starts at 0, 32, 64, 96, 128, 160, 192 and 224.
A /26 with the subnet mask 255.255.255.192 has 64 IP addresses, it starts at 0, 64, 128 and 192.
You try to configure two subnets that both start a 0. The first 32 IP addresses of the /26 overlaps with the /27.
HTH!
Bye, Tore
baher 1
08-26-2011, 01:21 PM
Hello,
a /27 with the subnet nask 255.255.255.224 has 32 IP addresses, it starts at 0, 32, 64, 96, 128, 160, 192 and 224.
A /26 with the subnet mask 255.255.255.192 has 64 IP addresses, it starts at 0, 64, 128 and 192.
You try to configure two subnets that both start a 0. The first 32 IP addresses of the /26 overlaps with the /27.
HTH!
Bye, Tore
how i resolve this problem
i wnant use ip 10.0.1.0 to make 2 network have 30 & 60 hosts
crissa
08-26-2011, 01:33 PM
how i resolve this problem
i wnant use ip 10.0.1.0 to make 2 network have 30 & 60 hosts
Hello,
you could use:
10.0.1.0/27
10.0.1.64/26
But that creates 32 unused IP addresses (10.0.1.32/27). So please use:
10.0.1.64/27
10.0.1.0/26
HTH!
Bye, Tore
baher 1
08-26-2011, 02:14 PM
Hello,
you could use:
10.0.1.0/27
10.0.1.64/26
But that creates 32 unused IP addresses (10.0.1.32/27). So please use:
10.0.1.64/27
10.0.1.0/26
HTH!
Bye, Tore
thx u i tray it and it's ok
i use use /26 then /27 in this example
can i make it rule i use less mask then larger number of mask
for other example want make 3 network have 120 & 10 & 9 hosts
in ip add 10.0.1.0
10 hosts = /28 120 host = /25 5 hosts = /29
so be use /25 then /28 then /29
10.0.1.0/25
10.0.1.128/28
10.0.1.144/29
is my Deductive true or not ??? and if not why ????
crissa
08-26-2011, 03:21 PM
[...]
for other example want make 3 network have 120 & 10 & 9 hosts
in ip add 10.0.1.0
10 hosts = /28 120 host = /25 5 hosts = /29
so be use /25 then /28 then /29
10.0.1.0/25
10.0.1.128/28
10.0.1.144/29
is my Deductive true or not ??? and if not why ????
Hello,
you don't have to sort the subnets from greater subnets down to smaller subnets. You could also use:
10.0.1.0/25
10.0.1.128/29
10.0.1.144/28
Maybe it helps you to write down start and end of a subnet:
10.0.1.0/25 => 0 ... 127
10.0.1.128/28 => 128 ... 143
10.0.1.144/29 => 144 ... 151
or
10.0.1.0/25 => 0 ... 127
10.0.1.128/29 => 128 ... 135
10.0.1.144/28 => 144 ... 159
The /28 can't start at 136 as you can't divide 136 by 16. By you can divide 144 by 16!
HTH!
Bye, Tore
baher 1
08-26-2011, 05:03 PM
ok
sorry last question
i have ip add 10.0.0.0
and i wnat make 3 network
have 600 & 500 & 100 hosts
what is the Solution
crissa
08-27-2011, 03:17 AM
ok
sorry last question
i have ip add 10.0.0.0
and i wnat make 3 network
have 600 & 500 & 100 hosts
what is the Solution
Hello,
one solution is:
600 => 1024 => /22
500 => 512 => /23
100 => 128 => /25
10.0.0.0/22
10.0.4.0/23
10.0.6.0/25
HTH!
Bye, Tore
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