Official Lammle User Forum
Errors in LAB 5
I believe that most of the answers to this lab are wrong.
188.8.131.52 to 184.108.40.206
15 = 00001111
so the first 20 bits are unchanged i.e. 220.127.116.11 /20
The answer given is 18.104.22.168/16 which would include for example 22.214.171.124
But the question is unclear because the CIDR notation is missing. without that this would be a Class A network and the IP addresses would both be on 126.96.36.199/8
192.168.1.0 - 192.168.120.0 again CIDR is missing so say we assume class C
the first 17 bits are unchanged 120<128
So a good summary would be 192.168.0.0/17
The answer given 192.168.0.0/25 which is only 192.168.0.0 - 192.168.0.127
Q2 the question gives two /13 networks. the answer /16 how can that be a summary.
188.8.131.52/12 I think works.
I could go on